Base | Representation |
---|---|
bin | 10111011100011111100… |
… | …100100100000000000101 |
3 | 12201000122021200202221220 |
4 | 113130133210210000011 |
5 | 202344104424224331 |
6 | 3232052033230553 |
7 | 224254416364035 |
oct | 27343744440005 |
9 | 5630567622856 |
10 | 1611142414341 |
11 | 571310988289 |
12 | 220300402459 |
13 | b8c124c4915 |
14 | 57da046d8c5 |
15 | 2bd99905296 |
hex | 1771f924005 |
1611142414341 has 4 divisors (see below), whose sum is σ = 2148189885792. Its totient is φ = 1074094942892.
The previous prime is 1611142414313. The next prime is 1611142414381. The reversal of 1611142414341 is 1434142411161.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1611142414341 - 211 = 1611142412293 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1611142414381) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 268523735721 + ... + 268523735726.
It is an arithmetic number, because the mean of its divisors is an integer number (537047471448).
Almost surely, 21611142414341 is an apocalyptic number.
It is an amenable number.
1611142414341 is a deficient number, since it is larger than the sum of its proper divisors (537047471451).
1611142414341 is an equidigital number, since it uses as much as digits as its factorization.
1611142414341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 537047471450.
The product of its digits is 9216, while the sum is 33.
The spelling of 1611142414341 in words is "one trillion, six hundred eleven billion, one hundred forty-two million, four hundred fourteen thousand, three hundred forty-one".
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