Base | Representation |
---|---|
bin | 100100101001111101101110… |
… | …000010000000100100001011 |
3 | 210010210212002001200111000122 |
4 | 210221331232002000210023 |
5 | 132112310113012210343 |
6 | 1330512233350053455 |
7 | 45646200262505552 |
oct | 4451755602004413 |
9 | 703725061614018 |
10 | 161213443475723 |
11 | 4740526801a691 |
12 | 160b82b404a28b |
13 | 6bc5493504ca2 |
14 | 2bb4ab527cd99 |
15 | 13987e93b0068 |
hex | 929f6e08090b |
161213443475723 has 4 divisors (see below), whose sum is σ = 161563147258128. Its totient is φ = 160863739693320.
The previous prime is 161213443475681. The next prime is 161213443475729. The reversal of 161213443475723 is 327574344312161.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 161213443475723 - 212 = 161213443471627 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (161213443475729) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 174851890511 + ... + 174851891432.
It is an arithmetic number, because the mean of its divisors is an integer number (40390786814532).
Almost surely, 2161213443475723 is an apocalyptic number.
161213443475723 is a deficient number, since it is larger than the sum of its proper divisors (349703782405).
161213443475723 is an equidigital number, since it uses as much as digits as its factorization.
161213443475723 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 349703782404.
The product of its digits is 10160640, while the sum is 53.
Adding to 161213443475723 its reverse (327574344312161), we get a palindrome (488787787787884).
The spelling of 161213443475723 in words is "one hundred sixty-one trillion, two hundred thirteen billion, four hundred forty-three million, four hundred seventy-five thousand, seven hundred twenty-three".
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