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16124214121 = 128312567587
BaseRepresentation
bin11110000010001001…
…11111101101101001
31112121201112221112121
433001010333231221
5231010244322441
611223553511241
71110400362421
oct170104775551
945551487477
1016124214121
1169247757a4
12315bb72521
13169c727302
14acd667481
1564587edd1
hex3c113fb69

16124214121 has 4 divisors (see below), whose sum is σ = 16136782992. Its totient is φ = 16111645252.

The previous prime is 16124214083. The next prime is 16124214151. The reversal of 16124214121 is 12141242161.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 16124214121 - 211 = 16124212073 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (16124214151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6282511 + ... + 6285076.

It is an arithmetic number, because the mean of its divisors is an integer number (4034195748).

Almost surely, 216124214121 is an apocalyptic number.

It is an amenable number.

16124214121 is a deficient number, since it is larger than the sum of its proper divisors (12568871).

16124214121 is a wasteful number, since it uses less digits than its factorization.

16124214121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12568870.

The product of its digits is 768, while the sum is 25.

Adding to 16124214121 its reverse (12141242161), we get a palindrome (28265456282).

The spelling of 16124214121 in words is "sixteen billion, one hundred twenty-four million, two hundred fourteen thousand, one hundred twenty-one".

Divisors: 1 1283 12567587 16124214121