1612510017131 has 4 divisors (see below), whose sum is σ = 1736549249232. Its totient is φ = 1488470785032.

The previous prime is 1612510017121. The next prime is 1612510017137. The reversal of 1612510017131 is 1317100152161.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1612510017131 is a prime.

It is a super-2 number, since 2×1612510017131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1612510017094 and 1612510017103.

It is not an unprimeable number, because it can be changed into a prime (1612510017137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 62019616031 + ... + 62019616056.

It is an arithmetic number, because the mean of its divisors is an integer number (434137312308).

Almost surely, 2^{1612510017131} is an apocalyptic number.

1612510017131 is a deficient number, since it is larger than the sum of its proper divisors (124039232101).

1612510017131 is a wasteful number, since it uses less digits than its factorization.

1612510017131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 124039232100.

The product of its (nonzero) digits is 1260, while the sum is 29.

Adding to 1612510017131 its reverse (1317100152161), we get a palindrome (2929610169292).

The spelling of 1612510017131 in words is "one trillion, six hundred twelve billion, five hundred ten million, seventeen thousand, one hundred thirty-one".