Search a number
-
+
16126577377117 = 29556088875073
BaseRepresentation
bin1110101010101100001011…
…1010100111111101011101
32010002200111220102210101221
43222223002322213331131
54103204212302031432
654144240344333341
73253051422663454
oct352530272477535
963080456383357
1016126577377117
115158274568349
121985532174251
138cc964275aac
143da75da0bb9b
151ce751518b97
hexeaac2ea7f5d

16126577377117 has 4 divisors (see below), whose sum is σ = 16682666252220. Its totient is φ = 15570488502016.

The previous prime is 16126577377073. The next prime is 16126577377123. The reversal of 16126577377117 is 71177377562161.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 5367613209721 + 10758964167396 = 2316811^2 + 3280086^2 .

It is a cyclic number.

It is not a de Polignac number, because 16126577377117 - 27 = 16126577376989 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (16126577317117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 278044437508 + ... + 278044437565.

It is an arithmetic number, because the mean of its divisors is an integer number (4170666563055).

Almost surely, 216126577377117 is an apocalyptic number.

It is an amenable number.

16126577377117 is a deficient number, since it is larger than the sum of its proper divisors (556088875103).

16126577377117 is an equidigital number, since it uses as much as digits as its factorization.

16126577377117 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 556088875102.

The product of its digits is 18151560, while the sum is 61.

The spelling of 16126577377117 in words is "sixteen trillion, one hundred twenty-six billion, five hundred seventy-seven million, three hundred seventy-seven thousand, one hundred seventeen".

Divisors: 1 29 556088875073 16126577377117