16130035 has 8 divisors (see below), whose sum is σ = 19393056. Its totient is φ = 12879360.

The previous prime is 16130027. The next prime is 16130041. The reversal of 16130035 is 53003161.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 16130035 - 2³ = 16130027 is a prime.

It is a super-3 number, since 3×16130035³ (a number of 23 digits) contains 333 as substring.

It is a Duffinian number.

It is a plaindrome in base 13.

It is a junction number, because it is equal to n+sod(n) for n = 16129994 and 16130021.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 90 + ... + 5680.

It is an arithmetic number, because the mean of its divisors is an integer number (2424132).

Almost surely, 2^16130035 is an apocalyptic number.

16130035 is a deficient number, since it is larger than the sum of its proper divisors (3263021).

16130035 is an equidigital number, since it uses as much as digits as its factorization.

16130035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6173.

The product of its (nonzero) digits is 270, while the sum is 19.

The square root of 16130035 is about 4016.2214829364. The cubic root of 16130035 is about 252.6650099406.

Adding to 16130035 its reverse (53003161), we get a palindrome (69133196).

The spelling of 16130035 in words is "sixteen million, one hundred thirty thousand, thirty-five".