Base | Representation |
---|---|
bin | 10111011110011100110… |
… | …011011010101000101101 |
3 | 12201020001201011221222000 |
4 | 113132130303122220231 |
5 | 202412410311211031 |
6 | 3233040330042513 |
7 | 224360451105015 |
oct | 27363463325055 |
9 | 5636051157860 |
10 | 1613243460141 |
11 | 572199970075 |
12 | 2207a7b79439 |
13 | b918888a7a1 |
14 | 5811d50cc45 |
15 | 2be6e0c73e6 |
hex | 1779ccdaa2d |
1613243460141 has 8 divisors (see below), whose sum is σ = 2389990311360. Its totient is φ = 1075495640076.
The previous prime is 1613243460139. The next prime is 1613243460187. The reversal of 1613243460141 is 1410643423161.
1613243460141 is a `hidden beast` number, since 1 + 6 + 1 + 3 + 2 + 4 + 3 + 4 + 601 + 41 = 666.
It is not a de Polignac number, because 1613243460141 - 21 = 1613243460139 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1613243460096 and 1613243460105.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1613243460121) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 29874878865 + ... + 29874878918.
It is an arithmetic number, because the mean of its divisors is an integer number (298748788920).
Almost surely, 21613243460141 is an apocalyptic number.
It is an amenable number.
1613243460141 is a deficient number, since it is larger than the sum of its proper divisors (776746851219).
1613243460141 is an equidigital number, since it uses as much as digits as its factorization.
1613243460141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 59749757792 (or 59749757786 counting only the distinct ones).
The product of its (nonzero) digits is 41472, while the sum is 36.
The spelling of 1613243460141 in words is "one trillion, six hundred thirteen billion, two hundred forty-three million, four hundred sixty thousand, one hundred forty-one".
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