161343340115 has 4 divisors (see below), whose sum is σ = 193612008144. Its totient is φ = 129074672088.

The previous prime is 161343340111. The next prime is 161343340133. The reversal of 161343340115 is 511043343161.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 161343340115 - 2² = 161343340111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (161343340111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16134334007 + ... + 16134334016.

It is an arithmetic number, because the mean of its divisors is an integer number (48403002036).

Almost surely, 2^161343340115 is an apocalyptic number.

161343340115 is a deficient number, since it is larger than the sum of its proper divisors (32268668029).

161343340115 is an equidigital number, since it uses as much as digits as its factorization.

161343340115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 32268668028.

The product of its (nonzero) digits is 12960, while the sum is 32.

Adding to 161343340115 its reverse (511043343161), we get a palindrome (672386683276).

The spelling of 161343340115 in words is "one hundred sixty-one billion, three hundred forty-three million, three hundred forty thousand, one hundred fifteen".