1614274432681 has 3 divisors (see below), whose sum is σ = 1614275703223. Its totient is φ = 1614273162140.

The previous prime is 1614274432637. The next prime is 1614274432691. The reversal of 1614274432681 is 1862344724161.

The square root of 1614274432681 is 1270541.

It is a perfect power (a square), and thus also a powerful number.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in only one way, i.e., 24809085081 + 1589465347600 = 157509^2 + 1260740^2 .

It is not a de Polignac number, because 1614274432681 - 2¹⁷ = 1614274301609 is a prime.

It is a super-2 number, since 2×1614274432681² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1614274432601) by changing a digit.

It is a polite number, since it can be written in 2 ways as a sum of consecutive naturals, for example, 635271 + ... + 1905811.

Almost surely, 2^{1614274432681} is an apocalyptic number.

1614274432681 is the 1270541-st square number.

1614274432681 is the 635271-st centered octagonal number.

It is an amenable number.

1614274432681 is a deficient number, since it is larger than the sum of its proper divisors (1270542).

1614274432681 is an frugal number, since it uses more digits than its factorization.

1614274432681 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2541082 (or 1270541 counting only the distinct ones).

The product of its digits is 1548288, while the sum is 49.

Multiplying 1614274432681 by its sum of digits (49), we get a square (79099447201369 = 8893787²).

The spelling of 1614274432681 in words is "one trillion, six hundred fourteen billion, two hundred seventy-four million, four hundred thirty-two thousand, six hundred eighty-one".