Base | Representation |
---|---|
bin | 1110101011101011110101… |
… | …0100010001001101001111 |
3 | 2010011022121122121212222011 |
4 | 3222322331110101031033 |
5 | 4103444210301234201 |
6 | 54200144015202051 |
7 | 3254225011662055 |
oct | 352727524211517 |
9 | 63138548555864 |
10 | 16143663305551 |
11 | 5164542087261 |
12 | 1988900216327 |
13 | 901457cc3b12 |
14 | 3db500c981d5 |
15 | 1cee01516151 |
hex | eaebd51134f |
16143663305551 has 4 divisors (see below), whose sum is σ = 16700341350600. Its totient is φ = 15586985260504.
The previous prime is 16143663305537. The next prime is 16143663305569. The reversal of 16143663305551 is 15550336634161.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 16143663305551 - 215 = 16143663272783 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 16143663305495 and 16143663305504.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (16143663300551) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 278339022481 + ... + 278339022538.
It is an arithmetic number, because the mean of its divisors is an integer number (4175085337650).
Almost surely, 216143663305551 is an apocalyptic number.
16143663305551 is a deficient number, since it is larger than the sum of its proper divisors (556678045049).
16143663305551 is an equidigital number, since it uses as much as digits as its factorization.
16143663305551 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 556678045048.
The product of its (nonzero) digits is 2916000, while the sum is 49.
The spelling of 16143663305551 in words is "sixteen trillion, one hundred forty-three billion, six hundred sixty-three million, three hundred five thousand, five hundred fifty-one".
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