1615640432133 has 72 divisors (see below), whose sum is σ = 2716674674400. Its totient is φ = 851202608256.

The previous prime is 1615640432111. The next prime is 1615640432149. The reversal of 1615640432133 is 3312340465161.

It is not a de Polignac number, because 1615640432133 - 2¹² = 1615640428037 is a prime.

It is a super-3 number, since 3×1615640432133³ (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (39).

It is a junction number, because it is equal to n+sod(n) for n = 1615640432091 and 1615640432100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1615640432533) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 21302283 + ... + 21377991.

It is an arithmetic number, because the mean of its divisors is an integer number (37731592700).

Almost surely, 2^{1615640432133} is an apocalyptic number.

1615640432133 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1615640432133 is a deficient number, since it is larger than the sum of its proper divisors (1101034242267).

1615640432133 is a wasteful number, since it uses less digits than its factorization.

1615640432133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 76611 (or 76591 counting only the distinct ones).

The product of its (nonzero) digits is 155520, while the sum is 39.

Adding to 1615640432133 its reverse (3312340465161), we get a palindrome (4927980897294).

The spelling of 1615640432133 in words is "one trillion, six hundred fifteen billion, six hundred forty million, four hundred thirty-two thousand, one hundred thirty-three".