Search a number
-
+
16220133418 = 28110066709
BaseRepresentation
bin11110001101100101…
…11001100000101010
31112212102001011002011
433012302321200222
5231204323232133
611241301430134
71112643600466
oct170662714052
945772034064
1016220133418
11697392a345
12318810b34a
1316b656c5a8
14adc2b54a6
1564deca6cd
hex3c6cb982a

16220133418 has 4 divisors (see below), whose sum is σ = 24330200130. Its totient is φ = 8110066708.

The previous prime is 16220133383. The next prime is 16220133431. The reversal of 16220133418 is 81433102261.

16220133418 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 11336499729 + 4883633689 = 106473^2 + 69883^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 16220133418.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4055033353 + ... + 4055033356.

Almost surely, 216220133418 is an apocalyptic number.

16220133418 is a deficient number, since it is larger than the sum of its proper divisors (8110066712).

16220133418 is an equidigital number, since it uses as much as digits as its factorization.

16220133418 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8110066711.

The product of its (nonzero) digits is 6912, while the sum is 31.

Adding to 16220133418 its reverse (81433102261), we get a palindrome (97653235679).

The spelling of 16220133418 in words is "sixteen billion, two hundred twenty million, one hundred thirty-three thousand, four hundred eighteen".

Divisors: 1 2 8110066709 16220133418