Base | Representation |
---|---|
bin | 11110001110111100… |
… | …11010011010110011 |
3 | 1112220012111200112002 |
4 | 33013132122122303 |
5 | 231220233243103 |
6 | 11242350124215 |
7 | 1113142550141 |
oct | 170736323263 |
9 | 45805450462 |
10 | 16231540403 |
11 | 697a310601 |
12 | 318bab066b |
13 | 16b8a346a0 |
14 | adda04591 |
15 | 64eed0488 |
hex | 3c779a6b3 |
16231540403 has 4 divisors (see below), whose sum is σ = 17480120448. Its totient is φ = 14982960360.
The previous prime is 16231540379. The next prime is 16231540433. The reversal of 16231540403 is 30404513261.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30404513261 = 2143 ⋅14187827.
It is a cyclic number.
It is not a de Polignac number, because 16231540403 - 28 = 16231540147 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (16231540433) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 624290003 + ... + 624290028.
It is an arithmetic number, because the mean of its divisors is an integer number (4370030112).
Almost surely, 216231540403 is an apocalyptic number.
16231540403 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
16231540403 is a deficient number, since it is larger than the sum of its proper divisors (1248580045).
16231540403 is a wasteful number, since it uses less digits than its factorization.
16231540403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1248580044.
The product of its (nonzero) digits is 8640, while the sum is 29.
The spelling of 16231540403 in words is "sixteen billion, two hundred thirty-one million, five hundred forty thousand, four hundred three".
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