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16231540433 is a prime number
BaseRepresentation
bin11110001110111100…
…11010011011010001
31112220012111200120012
433013132122123101
5231220233243213
611242350124305
71113142550213
oct170736323321
945805450505
1016231540433
11697a310629
12318bab0695
1316b8a346c4
14adda045b3
1564eed04a8
hex3c779a6d1

16231540433 has 2 divisors, whose sum is σ = 16231540434. Its totient is φ = 16231540432.

The previous prime is 16231540379. The next prime is 16231540477. The reversal of 16231540433 is 33404513261.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14551114384 + 1680426049 = 120628^2 + 40993^2 .

It is a cyclic number.

It is not a de Polignac number, because 16231540433 - 212 = 16231536337 is a prime.

It is a super-2 number, since 2×162315404332 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 16231540433.

It is not a weakly prime, because it can be changed into another prime (16231540133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8115770216 + 8115770217.

It is an arithmetic number, because the mean of its divisors is an integer number (8115770217).

Almost surely, 216231540433 is an apocalyptic number.

It is an amenable number.

16231540433 is a deficient number, since it is larger than the sum of its proper divisors (1).

16231540433 is an equidigital number, since it uses as much as digits as its factorization.

16231540433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 25920, while the sum is 32.

The spelling of 16231540433 in words is "sixteen billion, two hundred thirty-one million, five hundred forty thousand, four hundred thirty-three".