Base | Representation |
---|---|
bin | 11110010001011010… |
… | …00011100010000001 |
3 | 1112221122022001211221 |
4 | 33020231003202001 |
5 | 231241022443113 |
6 | 11244404035041 |
7 | 1113513022051 |
oct | 171055034201 |
9 | 45848261757 |
10 | 16252156033 |
11 | 698aa11413 |
12 | 3196992a81 |
13 | 16c00a2099 |
14 | b0264d561 |
15 | 651c0398d |
hex | 3c8b43881 |
16252156033 has 4 divisors (see below), whose sum is σ = 16305094960. Its totient is φ = 16199217108.
The previous prime is 16252156013. The next prime is 16252156051. The reversal of 16252156033 is 33065125261.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 16252156033 - 25 = 16252156001 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 16252156033.
It is not an unprimeable number, because it can be changed into a prime (16252156013) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26469003 + ... + 26469616.
It is an arithmetic number, because the mean of its divisors is an integer number (4076273740).
Almost surely, 216252156033 is an apocalyptic number.
It is an amenable number.
16252156033 is a deficient number, since it is larger than the sum of its proper divisors (52938927).
16252156033 is an equidigital number, since it uses as much as digits as its factorization.
16252156033 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 52938926.
The product of its (nonzero) digits is 32400, while the sum is 34.
The spelling of 16252156033 in words is "sixteen billion, two hundred fifty-two million, one hundred fifty-six thousand, thirty-three".
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