Base | Representation |
---|---|
bin | 10111101001101111011… |
… | …001100010011010010101 |
3 | 12202101100121000110010101 |
4 | 113221233121202122111 |
5 | 203112222322302123 |
6 | 3242403315054101 |
7 | 225300046114030 |
oct | 27515731423225 |
9 | 5671317013111 |
10 | 1625366603413 |
11 | 577350090043 |
12 | 22300bba1331 |
13 | ba36b3a9b47 |
14 | 5894d624017 |
15 | 2c42d56eaad |
hex | 17a6f662695 |
1625366603413 has 4 divisors (see below), whose sum is σ = 1857561832480. Its totient is φ = 1393171374348.
The previous prime is 1625366603389. The next prime is 1625366603459. The reversal of 1625366603413 is 3143066635261.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1625366603413 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1625366603513) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 116097614523 + ... + 116097614536.
It is an arithmetic number, because the mean of its divisors is an integer number (464390458120).
Almost surely, 21625366603413 is an apocalyptic number.
It is an amenable number.
1625366603413 is a deficient number, since it is larger than the sum of its proper divisors (232195229067).
1625366603413 is an equidigital number, since it uses as much as digits as its factorization.
1625366603413 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 232195229066.
The product of its (nonzero) digits is 1399680, while the sum is 46.
The spelling of 1625366603413 in words is "one trillion, six hundred twenty-five billion, three hundred sixty-six million, six hundred three thousand, four hundred thirteen".
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