Base | Representation |
---|---|
bin | 10111101010011101001… |
… | …100110100001001110111 |
3 | 12202110100010221001201120 |
4 | 113222131030310021313 |
5 | 203120311031121101 |
6 | 3243011444555023 |
7 | 225325066416045 |
oct | 27523514641167 |
9 | 5673303831646 |
10 | 1626135020151 |
11 | 5777049099a4 |
12 | 2231a53b2a73 |
13 | ba4616521c5 |
14 | 589c36cb395 |
15 | 2c475c58b36 |
hex | 17a9d334277 |
1626135020151 has 4 divisors (see below), whose sum is σ = 2168180026872. Its totient is φ = 1084090013432.
The previous prime is 1626135020141. The next prime is 1626135020173. The reversal of 1626135020151 is 1510205316261.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1626135020151 - 214 = 1626135003767 is a prime.
It is a super-2 number, since 2×16261350201512 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1626135020141) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 271022503356 + ... + 271022503361.
It is an arithmetic number, because the mean of its divisors is an integer number (542045006718).
Almost surely, 21626135020151 is an apocalyptic number.
1626135020151 is a deficient number, since it is larger than the sum of its proper divisors (542045006721).
1626135020151 is an equidigital number, since it uses as much as digits as its factorization.
1626135020151 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 542045006720.
The product of its (nonzero) digits is 10800, while the sum is 33.
The spelling of 1626135020151 in words is "one trillion, six hundred twenty-six billion, one hundred thirty-five million, twenty thousand, one hundred fifty-one".
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