Base | Representation |
---|---|
bin | 1001011101111101111… |
… | …1000001110101111101 |
3 | 120112212021120220202111 |
4 | 2113133133001311331 |
5 | 10131113242240013 |
6 | 202420525454021 |
7 | 14515642516306 |
oct | 2273737016575 |
9 | 515767526674 |
10 | 162663243133 |
11 | 62a92184146 |
12 | 27637711311 |
13 | 12453c53a31 |
14 | 7c314d97ad |
15 | 43706b173d |
hex | 25df7c1d7d |
162663243133 has 4 divisors (see below), whose sum is σ = 165091052800. Its totient is φ = 160235433468.
The previous prime is 162663243097. The next prime is 162663243157. The reversal of 162663243133 is 331342366261.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 331342366261 = 71 ⋅4666793891.
It is a cyclic number.
It is not a de Polignac number, because 162663243133 - 237 = 25224289661 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (162663243233) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1213904733 + ... + 1213904866.
It is an arithmetic number, because the mean of its divisors is an integer number (41272763200).
Almost surely, 2162663243133 is an apocalyptic number.
It is an amenable number.
162663243133 is a deficient number, since it is larger than the sum of its proper divisors (2427809667).
162663243133 is an equidigital number, since it uses as much as digits as its factorization.
162663243133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2427809666.
The product of its digits is 279936, while the sum is 40.
The spelling of 162663243133 in words is "one hundred sixty-two billion, six hundred sixty-three million, two hundred forty-three thousand, one hundred thirty-three".
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