Base | Representation |
---|---|
bin | 100101000011111110100001… |
… | …010011111101110100010011 |
3 | 210101010202002122212121211021 |
4 | 211003332201103331310103 |
5 | 132331102032103404321 |
6 | 1334401344053100311 |
7 | 46222301662215616 |
oct | 4503764123756423 |
9 | 711122078777737 |
10 | 163001010216211 |
11 | 47a34381926392 |
12 | 16346830627697 |
13 | 6cc4c108ca5ab |
14 | 2c3741068c17d |
15 | 13ca06c614941 |
hex | 943fa14fdd13 |
163001010216211 has 4 divisors (see below), whose sum is σ = 165233900767192. Its totient is φ = 160768119665232.
The previous prime is 163001010216193. The next prime is 163001010216263. The reversal of 163001010216211 is 112612010100361.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 163001010216211 - 233 = 162992420281619 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (163001010211211) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1116445275381 + ... + 1116445275526.
It is an arithmetic number, because the mean of its divisors is an integer number (41308475191798).
Almost surely, 2163001010216211 is an apocalyptic number.
163001010216211 is a deficient number, since it is larger than the sum of its proper divisors (2232890550981).
163001010216211 is an equidigital number, since it uses as much as digits as its factorization.
163001010216211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2232890550980.
The product of its (nonzero) digits is 432, while the sum is 25.
Adding to 163001010216211 its reverse (112612010100361), we get a palindrome (275613020316572).
The spelling of 163001010216211 in words is "one hundred sixty-three trillion, one billion, ten million, two hundred sixteen thousand, two hundred eleven".
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