Base | Representation |
---|---|
bin | 100101000110000001000101… |
… | …111101001000101110000011 |
3 | 210101122010222112012000001112 |
4 | 211012001011331020232003 |
5 | 132340401200111110132 |
6 | 1334550012103353535 |
7 | 46235364205640456 |
oct | 4506010575105603 |
9 | 711563875160045 |
10 | 163141211425667 |
11 | 47a88887849132 |
12 | 16369a397528ab |
13 | 70051c507b227 |
14 | 2c401108d549d |
15 | 13cda25d2dab2 |
hex | 946045f48b83 |
163141211425667 has 4 divisors (see below), whose sum is σ = 163141256005800. Its totient is φ = 163141166845536.
The previous prime is 163141211425663. The next prime is 163141211425723. The reversal of 163141211425667 is 766524112141361.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 163141211425667 - 22 = 163141211425663 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (163141211425663) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16256393 + ... + 24301290.
It is an arithmetic number, because the mean of its divisors is an integer number (40785314001450).
Almost surely, 2163141211425667 is an apocalyptic number.
163141211425667 is a deficient number, since it is larger than the sum of its proper divisors (44580133).
163141211425667 is an equidigital number, since it uses as much as digits as its factorization.
163141211425667 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 44580132.
The product of its digits is 1451520, while the sum is 50.
The spelling of 163141211425667 in words is "one hundred sixty-three trillion, one hundred forty-one billion, two hundred eleven million, four hundred twenty-five thousand, six hundred sixty-seven".
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