Base | Representation |
---|---|
bin | 11110011010110001… |
… | …01101010000001011 |
3 | 1120011010002220212021 |
4 | 33031120231100023 |
5 | 231421130123404 |
6 | 11300251425311 |
7 | 1115455504345 |
oct | 171530552013 |
9 | 46133086767 |
10 | 16330707979 |
11 | 6a20293683 |
12 | 31b9155237 |
13 | 1703446321 |
14 | b0cc5a295 |
15 | 658a6d454 |
hex | 3cd62d40b |
16330707979 has 4 divisors (see below), whose sum is σ = 16335226584. Its totient is φ = 16326189376.
The previous prime is 16330707971. The next prime is 16330707997. The reversal of 16330707979 is 97970703361.
16330707979 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 97970703361 = 53 ⋅1848503837.
It is a cyclic number.
It is not a de Polignac number, because 16330707979 - 23 = 16330707971 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (16330707971) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2253877 + ... + 2261110.
It is an arithmetic number, because the mean of its divisors is an integer number (4083806646).
Almost surely, 216330707979 is an apocalyptic number.
16330707979 is a deficient number, since it is larger than the sum of its proper divisors (4518605).
16330707979 is an equidigital number, since it uses as much as digits as its factorization.
16330707979 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4518604.
The product of its (nonzero) digits is 1500282, while the sum is 52.
The spelling of 16330707979 in words is "sixteen billion, three hundred thirty million, seven hundred seven thousand, nine hundred seventy-nine".
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