Base | Representation |
---|---|
bin | 100101001010011100001001… |
… | …000010001000111011111010 |
3 | 210102201012110021101002201211 |
4 | 211022130021002020323322 |
5 | 132410341112243130424 |
6 | 1335341353532233334 |
7 | 46266343511145661 |
oct | 4512341102107372 |
9 | 712635407332654 |
10 | 163445132005114 |
11 | 48095767013833 |
12 | 163b891800b84a |
13 | 7027a6b211b1b |
14 | 2c50b025d5dd8 |
15 | 13d68b27c5b94 |
hex | 94a709088efa |
163445132005114 has 8 divisors (see below), whose sum is σ = 247595100958548. Its totient is φ = 80913431685600.
The previous prime is 163445132005093. The next prime is 163445132005237. The reversal of 163445132005114 is 411500231544361.
It can be written as a sum of positive squares in 2 ways, for example, as 128943405855625 + 34501726149489 = 11355325^2 + 5873817^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-2 number, since 2×1634451320051142 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 404567158227 + ... + 404567158630.
Almost surely, 2163445132005114 is an apocalyptic number.
163445132005114 is a deficient number, since it is larger than the sum of its proper divisors (84149968953434).
163445132005114 is a wasteful number, since it uses less digits than its factorization.
163445132005114 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 809134316960.
The product of its (nonzero) digits is 172800, while the sum is 40.
Adding to 163445132005114 its reverse (411500231544361), we get a palindrome (574945363549475).
The spelling of 163445132005114 in words is "one hundred sixty-three trillion, four hundred forty-five billion, one hundred thirty-two million, five thousand, one hundred fourteen".
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