Base | Representation |
---|---|
bin | 100101001011111110110000… |
… | …011110110100100101110101 |
3 | 210110002022202211022201012220 |
4 | 211023332300132310211311 |
5 | 132414104442224043013 |
6 | 1335502145051032553 |
7 | 46310112516613401 |
oct | 4513766036644565 |
9 | 713068684281186 |
10 | 163551020534133 |
11 | 48126664363941 |
12 | 16415349a3b759 |
13 | 7034a4498b55b |
14 | 2c55ca972a101 |
15 | 13d950d979b23 |
hex | 94bfb07b4975 |
163551020534133 has 8 divisors (see below), whose sum is σ = 218119592311200. Its totient is φ = 109008231223248.
The previous prime is 163551020534131. The next prime is 163551020534171. The reversal of 163551020534133 is 331435020155361.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 163551020534133 - 21 = 163551020534131 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (163551020534131) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6445601743 + ... + 6445627116.
It is an arithmetic number, because the mean of its divisors is an integer number (27264949038900).
Almost surely, 2163551020534133 is an apocalyptic number.
It is an amenable number.
163551020534133 is a deficient number, since it is larger than the sum of its proper divisors (54568571777067).
163551020534133 is a wasteful number, since it uses less digits than its factorization.
163551020534133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12891233091.
The product of its (nonzero) digits is 486000, while the sum is 42.
Adding to 163551020534133 its reverse (331435020155361), we get a palindrome (494986040689494).
The spelling of 163551020534133 in words is "one hundred sixty-three trillion, five hundred fifty-one billion, twenty million, five hundred thirty-four thousand, one hundred thirty-three".
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