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16393470451 = 103333158647
BaseRepresentation
bin11110100010010000…
…01000000111110011
31120022111012120210021
433101020020013303
5232033212023301
611310412544311
71120150125331
oct172110100763
946274176707
1016393470451
116a52760a96
123216182097
13171344c797
14b17316b51
1565e3198a1
hex3d12081f3

16393470451 has 4 divisors (see below), whose sum is σ = 16393732432. Its totient is φ = 16393208472.

The previous prime is 16393470391. The next prime is 16393470461. The reversal of 16393470451 is 15407439361.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 15407439361 = 35343647137.

It is a cyclic number.

It is not a de Polignac number, because 16393470451 - 231 = 14245986803 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 16393470398 and 16393470407.

It is not an unprimeable number, because it can be changed into a prime (16393470461) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24010 + ... + 182656.

It is an arithmetic number, because the mean of its divisors is an integer number (4098433108).

Almost surely, 216393470451 is an apocalyptic number.

16393470451 is a deficient number, since it is larger than the sum of its proper divisors (261981).

16393470451 is a wasteful number, since it uses less digits than its factorization.

16393470451 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 261980.

The product of its (nonzero) digits is 272160, while the sum is 43.

The spelling of 16393470451 in words is "sixteen billion, three hundred ninety-three million, four hundred seventy thousand, four hundred fifty-one".

Divisors: 1 103333 158647 16393470451