1640131003 has 8 divisors (see below), whose sum is σ = 1874993120. Its totient is φ = 1405408320.

The previous prime is 1640131001. The next prime is 1640131007. The reversal of 1640131003 is 3001310461.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1640131003 - 2¹ = 1640131001 is a prime.

It is a super-3 number, since 3×1640131003³ (a number of 29 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (1640131001) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8298 + ... + 57871.

It is an arithmetic number, because the mean of its divisors is an integer number (234374140).

Almost surely, 2^1640131003 is an apocalyptic number.

1640131003 is a deficient number, since it is larger than the sum of its proper divisors (234862117).

1640131003 is an equidigital number, since it uses as much as digits as its factorization.

1640131003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 69717.

The product of its (nonzero) digits is 216, while the sum is 19.

The square root of 1640131003 is about 40498.5308745885. The cubic root of 1640131003 is about 1179.3051072380.

Adding to 1640131003 its reverse (3001310461), we get a palindrome (4641441464).

The spelling of 1640131003 in words is "one billion, six hundred forty million, one hundred thirty-one thousand, three".