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BaseRepresentation
bin110111010101
311212011
4313111
5103131
624221
713216
oct6725
94764
103541
11272a
122071
1317c5
14140d
1510b1
hexdd5

3541 has 2 divisors, whose sum is σ = 3542. Its totient is φ = 3540.

The previous prime is 3539. The next prime is 3547. The reversal of 3541 is 1453.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2916 + 625 = 54^2 + 25^2 .

It is an emirp because it is prime and its reverse (1453) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3541 - 21 = 3539 is a prime.

Together with 3539, it forms a pair of twin primes.

It is a Chen prime.

It is the 60-th Hogben number.

It is a nialpdrome in base 16.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3547) by changing a digit.

It is a nontrivial repunit in base 59.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1770 + 1771.

It is an arithmetic number, because the mean of its divisors is an integer number (1771).

It is an amenable number.

3541 is a deficient number, since it is larger than the sum of its proper divisors (1).

3541 is an equidigital number, since it uses as much as digits as its factorization.

3541 is an evil number, because the sum of its binary digits is even.

The product of its digits is 60, while the sum is 13.

The square root of 3541 is about 59.5063021872. The cubic root of 3541 is about 15.2420006421.

Subtracting from 3541 its product of digits (60), we obtain a square (3481 = 592).

Adding to 3541 its reverse (1453), we get a palindrome (4994).

The spelling of 3541 in words is "three thousand, five hundred forty-one".