164025119 has 4 divisors (see below), whose sum is σ = 172658040. Its totient is φ = 155392200.

The previous prime is 164025101. The next prime is 164025137. The reversal of 164025119 is 911520461.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 911520461 = 67 ⋅13604783.

It is an interprime number because it is at equal distance from previous prime (164025101) and next prime (164025137).

It is a cyclic number.

It is not a de Polignac number, because 164025119 - 2²⁰ = 162976543 is a prime.

It is a super-3 number, since 3×164025119³ (a number of 26 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 164025091 and 164025100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (164025139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4316432 + ... + 4316469.

It is an arithmetic number, because the mean of its divisors is an integer number (43164510).

Almost surely, 2^164025119 is an apocalyptic number.

164025119 is a gapful number since it is divisible by the number (19) formed by its first and last digit.

164025119 is a deficient number, since it is larger than the sum of its proper divisors (8632921).

164025119 is an equidigital number, since it uses as much as digits as its factorization.

164025119 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8632920.

The product of its (nonzero) digits is 2160, while the sum is 29.

The square root of 164025119 is about 12807.2291694964. The cubic root of 164025119 is about 547.3983119805.

The spelling of 164025119 in words is "one hundred sixty-four million, twenty-five thousand, one hundred nineteen".