Base | Representation |
---|---|
bin | 1110111010111011010111… |
… | …0111011100010000110001 |
3 | 2011002100112200110222222022 |
4 | 3232232311313130100301 |
5 | 4122242012004010301 |
6 | 54520332543321225 |
7 | 3312155234216162 |
oct | 356566567342061 |
9 | 64070480428868 |
10 | 16405531313201 |
11 | 525560180a298 |
12 | 1a0b6032b0215 |
13 | 92005ba81c34 |
14 | 40a063969769 |
15 | 1d6b2b1cbd1b |
hex | eebb5ddc431 |
16405531313201 has 32 divisors (see below), whose sum is σ = 16796239917600. Its totient is φ = 16020774604800.
The previous prime is 16405531313167. The next prime is 16405531313219. The reversal of 16405531313201 is 10231313550461.
It can be written as a sum of positive squares in 16 ways, for example, as 6973169736976 + 9432361576225 = 2640676^2 + 3071215^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-16405531313201 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (16405531313261) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4540693271 + ... + 4540696883.
It is an arithmetic number, because the mean of its divisors is an integer number (524882497425).
Almost surely, 216405531313201 is an apocalyptic number.
It is an amenable number.
16405531313201 is a deficient number, since it is larger than the sum of its proper divisors (390708604399).
16405531313201 is a wasteful number, since it uses less digits than its factorization.
16405531313201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5589.
The product of its (nonzero) digits is 32400, while the sum is 35.
Adding to 16405531313201 its reverse (10231313550461), we get a palindrome (26636844863662).
The spelling of 16405531313201 in words is "sixteen trillion, four hundred five billion, five hundred thirty-one million, three hundred thirteen thousand, two hundred one".
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