Base | Representation |
---|---|
bin | 1110111100100010101000… |
… | …1011001101101010001111 |
3 | 2011012000002121201000110201 |
4 | 3233020222023031222033 |
5 | 4123220300112111403 |
6 | 54541155411514331 |
7 | 3314156213105536 |
oct | 357105213155217 |
9 | 64160077630421 |
10 | 16433252457103 |
11 | 5266337663a79 |
12 | 1a14a5abb89a7 |
13 | 922858c95b71 |
14 | 40b53348b31d |
15 | 1d76eec0e21d |
hex | ef22a2cda8f |
16433252457103 has 4 divisors (see below), whose sum is σ = 16543542742200. Its totient is φ = 16322962172008.
The previous prime is 16433252457071. The next prime is 16433252457109. The reversal of 16433252457103 is 30175425233461.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 16433252457103 - 25 = 16433252457071 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (16433252457109) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55145142325 + ... + 55145142622.
It is an arithmetic number, because the mean of its divisors is an integer number (4135885685550).
Almost surely, 216433252457103 is an apocalyptic number.
16433252457103 is a deficient number, since it is larger than the sum of its proper divisors (110290285097).
16433252457103 is a wasteful number, since it uses less digits than its factorization.
16433252457103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 110290285096.
The product of its (nonzero) digits is 1814400, while the sum is 46.
The spelling of 16433252457103 in words is "sixteen trillion, four hundred thirty-three billion, two hundred fifty-two million, four hundred fifty-seven thousand, one hundred three".
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