Base | Representation |
---|---|
bin | 11110100111110110… |
… | …01111100111011011 |
3 | 1120102202120010012210 |
4 | 33103323033213123 |
5 | 232132222044143 |
6 | 11315211210203 |
7 | 1121260206666 |
oct | 172373174733 |
9 | 46382503183 |
10 | 16440424923 |
11 | 6a7721163a |
12 | 3229a46963 |
13 | 17200ac8b0 |
14 | b1d65a6dd |
15 | 6634e2033 |
hex | 3d3ecf9db |
16440424923 has 32 divisors (see below), whose sum is σ = 25013463552. Its totient is φ = 9515174400.
The previous prime is 16440424883. The next prime is 16440424927. The reversal of 16440424923 is 32942404461.
It is not a de Polignac number, because 16440424923 - 210 = 16440423899 is a prime.
It is a super-3 number, since 3×164404249233 (a number of 32 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (39).
It is not an unprimeable number, because it can be changed into a prime (16440424927) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 993588 + ... + 1009998.
It is an arithmetic number, because the mean of its divisors is an integer number (781670736).
Almost surely, 216440424923 is an apocalyptic number.
16440424923 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
16440424923 is a deficient number, since it is larger than the sum of its proper divisors (8573038629).
16440424923 is a wasteful number, since it uses less digits than its factorization.
16440424923 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17955.
The product of its (nonzero) digits is 165888, while the sum is 39.
The spelling of 16440424923 in words is "sixteen billion, four hundred forty million, four hundred twenty-four thousand, nine hundred twenty-three".
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