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16441325403 = 325409215689
BaseRepresentation
bin11110100111111101…
…01011011101011011
31120102211020212102220
433103332223131123
5232132434403103
611315242355123
71121300650206
oct172376533533
946384225386
1016441325403
116a77777138
12322a1bbaa3
131720336719
14b1d81293d
1566361dc53
hex3d3fab75b

16441325403 has 8 divisors (see below), whose sum is σ = 21922731600. Its totient is φ = 10960401408.

The previous prime is 16441325393. The next prime is 16441325441. The reversal of 16441325403 is 30452314461.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 16441325403 - 224 = 16424548187 is a prime.

It is a super-3 number, since 3×164413254033 (a number of 32 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not an unprimeable number, because it can be changed into a prime (16441325443) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 31618 + ... + 184071.

It is an arithmetic number, because the mean of its divisors is an integer number (2740341450).

Almost surely, 216441325403 is an apocalyptic number.

16441325403 is a deficient number, since it is larger than the sum of its proper divisors (5481406197).

16441325403 is a wasteful number, since it uses less digits than its factorization.

16441325403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 241101.

The product of its (nonzero) digits is 34560, while the sum is 33.

Adding to 16441325403 its reverse (30452314461), we get a palindrome (46893639864).

The spelling of 16441325403 in words is "sixteen billion, four hundred forty-one million, three hundred twenty-five thousand, four hundred three".

Divisors: 1 3 25409 76227 215689 647067 5480441801 16441325403