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16443014703657 = 35481004901219
BaseRepresentation
bin1110111101000111000000…
…0011001110101000101001
32011012221021222002112011220
43233101300003032220221
54123400243231004112
654545452222412253
73314653142613003
oct357216003165051
964187258075156
1016443014703657
11526a49714a333
121a16924431089
1392375363ac09
1440bbbbc01373
151d7ac1ca698c
hexef4700cea29

16443014703657 has 4 divisors (see below), whose sum is σ = 21924019604880. Its totient is φ = 10962009802436.

The previous prime is 16443014703649. The next prime is 16443014703719. The reversal of 16443014703657 is 75630741034461.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 16443014703657 - 23 = 16443014703649 is a prime.

It is a super-3 number, since 3×164430147036573 (a number of 41 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (16443014703757) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2740502450607 + ... + 2740502450612.

It is an arithmetic number, because the mean of its divisors is an integer number (5481004901220).

Almost surely, 216443014703657 is an apocalyptic number.

It is an amenable number.

16443014703657 is a deficient number, since it is larger than the sum of its proper divisors (5481004901223).

16443014703657 is an equidigital number, since it uses as much as digits as its factorization.

16443014703657 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5481004901222.

The product of its (nonzero) digits is 5080320, while the sum is 51.

The spelling of 16443014703657 in words is "sixteen trillion, four hundred forty-three billion, fourteen million, seven hundred three thousand, six hundred fifty-seven".

Divisors: 1 3 5481004901219 16443014703657