Base | Representation |
---|---|
bin | 1110111101000111001010… |
… | …0000010101111001110011 |
3 | 2011012221101211121000021022 |
4 | 3233101302200111321303 |
5 | 4123400334301440120 |
6 | 54545500253250055 |
7 | 3314654152651625 |
oct | 357216240257163 |
9 | 64187354530238 |
10 | 16443055890035 |
11 | 526a508420265 |
12 | 1a1693619392b |
13 | 92375c02b758 |
14 | 40bbc3482c15 |
15 | 1d7ac56e0025 |
hex | ef472815e73 |
16443055890035 has 4 divisors (see below), whose sum is σ = 19731667068048. Its totient is φ = 13154444712024.
The previous prime is 16443055890029. The next prime is 16443055890049. The reversal of 16443055890035 is 53009855034461.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-16443055890035 is a prime.
It is a super-3 number, since 3×164430558900353 (a number of 41 digits) contains 333 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1644305588999 + ... + 1644305589008.
It is an arithmetic number, because the mean of its divisors is an integer number (4932916767012).
Almost surely, 216443055890035 is an apocalyptic number.
16443055890035 is a deficient number, since it is larger than the sum of its proper divisors (3288611178013).
16443055890035 is an equidigital number, since it uses as much as digits as its factorization.
16443055890035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3288611178012.
The product of its (nonzero) digits is 7776000, while the sum is 53.
The spelling of 16443055890035 in words is "sixteen trillion, four hundred forty-three billion, fifty-five million, eight hundred ninety thousand, thirty-five".
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