Base | Representation |
---|---|
bin | 100101011010001000111010… |
… | …100110000111111100011001 |
3 | 210120112100012110102200122021 |
4 | 211122020322212013330121 |
5 | 133031030123040004423 |
6 | 1341525140552254441 |
7 | 46440316046360020 |
oct | 4532107246077431 |
9 | 716470173380567 |
10 | 164524000313113 |
11 | 48471267054861 |
12 | 16551a2a9a1421 |
13 | 70a571501661c |
14 | 2c8b00b3898b7 |
15 | 14049a7eb495d |
hex | 95a23a987f19 |
164524000313113 has 4 divisors (see below), whose sum is σ = 188027428929280. Its totient is φ = 141020571696948.
The previous prime is 164524000313111. The next prime is 164524000313227. The reversal of 164524000313113 is 311313000425461.
164524000313113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 164524000313113 - 21 = 164524000313111 is a prime.
It is a super-4 number, since 4×1645240003131134 (a number of 58 digits) contains 4444 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (164524000313111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11751714308073 + ... + 11751714308086.
It is an arithmetic number, because the mean of its divisors is an integer number (47006857232320).
Almost surely, 2164524000313113 is an apocalyptic number.
It is an amenable number.
164524000313113 is a deficient number, since it is larger than the sum of its proper divisors (23503428616167).
164524000313113 is an equidigital number, since it uses as much as digits as its factorization.
164524000313113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23503428616166.
The product of its (nonzero) digits is 25920, while the sum is 34.
Adding to 164524000313113 its reverse (311313000425461), we get a palindrome (475837000738574).
The spelling of 164524000313113 in words is "one hundred sixty-four trillion, five hundred twenty-four billion, three hundred thirteen thousand, one hundred thirteen".
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