165000317 has 4 divisors (see below), whose sum is σ = 174706236. Its totient is φ = 155294400.

The previous prime is 165000301. The next prime is 165000377. The reversal of 165000317 is 713000561.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 88717561 + 76282756 = 9419^2 + 8734^2 .

It is a cyclic number.

It is not a de Polignac number, because 165000317 - 2⁴ = 165000301 is a prime.

It is a super-2 number, since 2×165000317² = 54450209220200978, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 165000292 and 165000301.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (165000377) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4852934 + ... + 4852967.

It is an arithmetic number, because the mean of its divisors is an integer number (43676559).

Almost surely, 2^165000317 is an apocalyptic number.

165000317 is a gapful number since it is divisible by the number (17) formed by its first and last digit.

It is an amenable number.

165000317 is a deficient number, since it is larger than the sum of its proper divisors (9705919).

165000317 is an equidigital number, since it uses as much as digits as its factorization.

165000317 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9705918.

The product of its (nonzero) digits is 630, while the sum is 23.

The square root of 165000317 is about 12845.2449178675. The cubic root of 165000317 is about 548.4810064923.

Adding to 165000317 its reverse (713000561), we get a palindrome (878000878).

The spelling of 165000317 in words is "one hundred sixty-five million, three hundred seventeen", and thus it is an aban number.