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165317441133 = 31317872372081
BaseRepresentation
bin1001100111110110101…
…1111111011001101101
3120210201020221010221010
42121331223333121231
510202032231104013
6203540142255433
714641502031015
oct2317553773155
9523636833833
10165317441133
1164124427409
1228058587579
1312787ac1ab0
148003c08c45
1544786ea7c3
hex267daff66d

165317441133 has 16 divisors (see below), whose sum is σ = 237511826496. Its totient is φ = 101676837120.

The previous prime is 165317441119. The next prime is 165317441153. The reversal of 165317441133 is 331144713561.

It is not a de Polignac number, because 165317441133 - 221 = 165315343981 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (39).

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 165317441091 and 165317441100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (165317441153) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1116348 + ... + 1255733.

It is an arithmetic number, because the mean of its divisors is an integer number (14844489156).

Almost surely, 2165317441133 is an apocalyptic number.

165317441133 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

165317441133 is a deficient number, since it is larger than the sum of its proper divisors (72194385363).

165317441133 is a wasteful number, since it uses less digits than its factorization.

165317441133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2373884.

The product of its digits is 90720, while the sum is 39.

The spelling of 165317441133 in words is "one hundred sixty-five billion, three hundred seventeen million, four hundred forty-one thousand, one hundred thirty-three".

Divisors: 1 3 13 39 1787 5361 23231 69693 2372081 7116243 30837053 92511159 4238908747 12716726241 55105813711 165317441133