Base | Representation |
---|---|
bin | 1001100111110110101… |
… | …1111111011001101101 |
3 | 120210201020221010221010 |
4 | 2121331223333121231 |
5 | 10202032231104013 |
6 | 203540142255433 |
7 | 14641502031015 |
oct | 2317553773155 |
9 | 523636833833 |
10 | 165317441133 |
11 | 64124427409 |
12 | 28058587579 |
13 | 12787ac1ab0 |
14 | 8003c08c45 |
15 | 44786ea7c3 |
hex | 267daff66d |
165317441133 has 16 divisors (see below), whose sum is σ = 237511826496. Its totient is φ = 101676837120.
The previous prime is 165317441119. The next prime is 165317441153. The reversal of 165317441133 is 331144713561.
It is not a de Polignac number, because 165317441133 - 221 = 165315343981 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (39).
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 165317441091 and 165317441100.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (165317441153) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1116348 + ... + 1255733.
It is an arithmetic number, because the mean of its divisors is an integer number (14844489156).
Almost surely, 2165317441133 is an apocalyptic number.
165317441133 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
165317441133 is a deficient number, since it is larger than the sum of its proper divisors (72194385363).
165317441133 is a wasteful number, since it uses less digits than its factorization.
165317441133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2373884.
The product of its digits is 90720, while the sum is 39.
The spelling of 165317441133 in words is "one hundred sixty-five billion, three hundred seventeen million, four hundred forty-one thousand, one hundred thirty-three".
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