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16534026113 = 111503093283
BaseRepresentation
bin11110110011000000…
…10011011110000001
31120200021200112220112
433121200103132001
5232330202313423
611332353321105
71123504621523
oct173140233601
946607615815
1016534026113
1170150325a0
123255266195
1317365c2a07
14b2bc63a13
1566b830a78
hex3d9813781

16534026113 has 4 divisors (see below), whose sum is σ = 18037119408. Its totient is φ = 15030932820.

The previous prime is 16534026101. The next prime is 16534026139. The reversal of 16534026113 is 31162043561.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 16534026113 - 210 = 16534025089 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 16534026113.

It is not an unprimeable number, because it can be changed into a prime (16534026143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 751546631 + ... + 751546652.

It is an arithmetic number, because the mean of its divisors is an integer number (4509279852).

Almost surely, 216534026113 is an apocalyptic number.

It is an amenable number.

16534026113 is a deficient number, since it is larger than the sum of its proper divisors (1503093295).

16534026113 is a wasteful number, since it uses less digits than its factorization.

16534026113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1503093294.

The product of its (nonzero) digits is 12960, while the sum is 32.

Adding to 16534026113 its reverse (31162043561), we get a palindrome (47696069674).

The spelling of 16534026113 in words is "sixteen billion, five hundred thirty-four million, twenty-six thousand, one hundred thirteen".

Divisors: 1 11 1503093283 16534026113