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166071131252447 = 295726590732843
BaseRepresentation
bin100101110000101001110010…
…110010010010011011011111
3210210000020121200020121122112
4211300221302302102123133
5133231402134100034242
61345112005141504235
746660146306361001
oct4560516262223337
9723006550217575
10166071131252447
1148a0840a143483
1216761845a1207b
1371885959725c5
142d01c582a6371
15142ed57dc6c82
hex970a72c926df

166071131252447 has 4 divisors (see below), whose sum is σ = 171797721985320. Its totient is φ = 160344540519576.

The previous prime is 166071131252357. The next prime is 166071131252473. The reversal of 166071131252447 is 744252131170661.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 166071131252447 - 214 = 166071131236063 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 166071131252395 and 166071131252404.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (166071131252947) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2863295366393 + ... + 2863295366450.

It is an arithmetic number, because the mean of its divisors is an integer number (42949430496330).

Almost surely, 2166071131252447 is an apocalyptic number.

166071131252447 is a deficient number, since it is larger than the sum of its proper divisors (5726590732873).

166071131252447 is an equidigital number, since it uses as much as digits as its factorization.

166071131252447 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5726590732872.

The product of its (nonzero) digits is 1693440, while the sum is 50.

The spelling of 166071131252447 in words is "one hundred sixty-six trillion, seventy-one billion, one hundred thirty-one million, two hundred fifty-two thousand, four hundred forty-seven".

Divisors: 1 29 5726590732843 166071131252447