Base | Representation |
---|---|
bin | 1001101100111100011… |
… | …1101000110111001101 |
3 | 120221020110200102000220 |
4 | 2123033013220313031 |
5 | 10212332003041331 |
6 | 204323504541553 |
7 | 15020401406565 |
oct | 2331707506715 |
9 | 527213612026 |
10 | 166683643341 |
11 | 64765631346 |
12 | 2837a0218b9 |
13 | 12944b68a77 |
14 | 80d343dda5 |
15 | 4508616296 |
hex | 26cf1e8dcd |
166683643341 has 4 divisors (see below), whose sum is σ = 222244857792. Its totient is φ = 111122428892.
The previous prime is 166683643283. The next prime is 166683643363. The reversal of 166683643341 is 143346386661.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 143346386661 = 3 ⋅47782128887.
It is a cyclic number.
It is not a de Polignac number, because 166683643341 - 222 = 166679449037 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (166683643381) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27780607221 + ... + 27780607226.
It is an arithmetic number, because the mean of its divisors is an integer number (55561214448).
Almost surely, 2166683643341 is an apocalyptic number.
It is an amenable number.
166683643341 is a deficient number, since it is larger than the sum of its proper divisors (55561214451).
166683643341 is an equidigital number, since it uses as much as digits as its factorization.
166683643341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 55561214450.
The product of its digits is 4478976, while the sum is 51.
The spelling of 166683643341 in words is "one hundred sixty-six billion, six hundred eighty-three million, six hundred forty-three thousand, three hundred forty-one".
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