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16852020020335 = 53370404004067
BaseRepresentation
bin1111010100111010101010…
…1010101100010001101111
32012200001000020202101022001
43311032222222230101233
54202100414111122320
655501413334033131
73356342523500413
oct365165252542157
965601006671261
1016852020020335
1154079a0a74405
121a8204b4a87a7
139531a586b4b6
144238dbda0d43
151e355e07c20a
hexf53aaaac46f

16852020020335 has 4 divisors (see below), whose sum is σ = 20222424024408. Its totient is φ = 13481616016264.

The previous prime is 16852020020327. The next prime is 16852020020351. The reversal of 16852020020335 is 53302002025861.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 16852020020335 - 23 = 16852020020327 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 16852020020294 and 16852020020303.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1685202002029 + ... + 1685202002038.

It is an arithmetic number, because the mean of its divisors is an integer number (5055606006102).

Almost surely, 216852020020335 is an apocalyptic number.

16852020020335 is a deficient number, since it is larger than the sum of its proper divisors (3370404004073).

16852020020335 is an equidigital number, since it uses as much as digits as its factorization.

16852020020335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3370404004072.

The product of its (nonzero) digits is 86400, while the sum is 37.

The spelling of 16852020020335 in words is "sixteen trillion, eight hundred fifty-two billion, twenty million, twenty thousand, three hundred thirty-five".

Divisors: 1 5 3370404004067 16852020020335