Base | Representation |
---|---|
bin | 1001110100011001010… |
… | …0101100101001101001 |
3 | 121010101211212110200010 |
4 | 2131012110230221221 |
5 | 10230430442233213 |
6 | 205254150002133 |
7 | 15121064364231 |
oct | 2350624545151 |
9 | 533354773603 |
10 | 168683555433 |
11 | 655a1518958 |
12 | 28837946349 |
13 | 12ba32b20c3 |
14 | 8242cb4cc1 |
15 | 45c3eacac3 |
hex | 274652ca69 |
168683555433 has 4 divisors (see below), whose sum is σ = 224911407248. Its totient is φ = 112455703620.
The previous prime is 168683555413. The next prime is 168683555437. The reversal of 168683555433 is 334555386861.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 168683555433 - 214 = 168683539049 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (168683555437) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28113925903 + ... + 28113925908.
It is an arithmetic number, because the mean of its divisors is an integer number (56227851812).
Almost surely, 2168683555433 is an apocalyptic number.
It is an amenable number.
168683555433 is a deficient number, since it is larger than the sum of its proper divisors (56227851815).
168683555433 is an equidigital number, since it uses as much as digits as its factorization.
168683555433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 56227851814.
The product of its digits is 31104000, while the sum is 57.
The spelling of 168683555433 in words is "one hundred sixty-eight billion, six hundred eighty-three million, five hundred fifty-five thousand, four hundred thirty-three".
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