Base | Representation |
---|---|
bin | 100110011001101000011100… |
… | …110000010011111110111001 |
3 | 211010222110100101220020122202 |
4 | 212121220130300103332321 |
5 | 134114021424212040441 |
6 | 1355105411413355545 |
7 | 50400460630463312 |
oct | 4631503460237671 |
9 | 733873311806582 |
10 | 168887186440121 |
11 | 498a37209580a6 |
12 | 16b37575038bb5 |
13 | 7330cbb4bcc96 |
14 | 2d9c27d4d7609 |
15 | 147d22393e19b |
hex | 999a1cc13fb9 |
168887186440121 has 4 divisors (see below), whose sum is σ = 172480530832512. Its totient is φ = 165293842047732.
The previous prime is 168887186440117. The next prime is 168887186440129. The reversal of 168887186440121 is 121044681788861.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 168887186440121 - 22 = 168887186440117 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (168887186440129) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1796672196125 + ... + 1796672196218.
It is an arithmetic number, because the mean of its divisors is an integer number (43120132708128).
Almost surely, 2168887186440121 is an apocalyptic number.
It is an amenable number.
168887186440121 is a deficient number, since it is larger than the sum of its proper divisors (3593344392391).
168887186440121 is an equidigital number, since it uses as much as digits as its factorization.
168887186440121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3593344392390.
The product of its (nonzero) digits is 33030144, while the sum is 65.
The spelling of 168887186440121 in words is "one hundred sixty-eight trillion, eight hundred eighty-seven billion, one hundred eighty-six million, four hundred forty thousand, one hundred twenty-one".
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