Search a number
-
+
16889400933 = 35629800311
BaseRepresentation
bin11111011101010111…
…11100111001100101
31121121001101110111220
433232223330321211
5234042141312213
611431530250553
71135351352646
oct175653747145
947531343456
1016889400933
117187698999
123334286a59
13179210b482
14b6312d6cd
1568cb2be23
hex3eeafce65

16889400933 has 4 divisors (see below), whose sum is σ = 22519201248. Its totient is φ = 11259600620.

The previous prime is 16889400929. The next prime is 16889400949. The reversal of 16889400933 is 33900498861.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 16889400933 - 22 = 16889400929 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (16889400923) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2814900153 + ... + 2814900158.

It is an arithmetic number, because the mean of its divisors is an integer number (5629800312).

Almost surely, 216889400933 is an apocalyptic number.

It is an amenable number.

16889400933 is a deficient number, since it is larger than the sum of its proper divisors (5629800315).

16889400933 is an equidigital number, since it uses as much as digits as its factorization.

16889400933 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5629800314.

The product of its (nonzero) digits is 1119744, while the sum is 51.

The spelling of 16889400933 in words is "sixteen billion, eight hundred eighty-nine million, four hundred thousand, nine hundred thirty-three".

Divisors: 1 3 5629800311 16889400933