Base | Representation |
---|---|
bin | 1111011000001100100111… |
… | …1011100110010000000001 |
3 | 2012212102111000100022121110 |
4 | 3312003021323212100001 |
5 | 4204011330023330031 |
6 | 55543334021113533 |
7 | 3363406253110251 |
oct | 366031173462001 |
9 | 65772430308543 |
10 | 16908379120641 |
11 | 5429892238658 |
12 | 1a90b59b588a9 |
13 | 9585b7bc8368 |
14 | 426527099961 |
15 | 1e4c5bd3ec46 |
hex | f60c9ee6401 |
16908379120641 has 4 divisors (see below), whose sum is σ = 22544505494192. Its totient is φ = 11272252747092.
The previous prime is 16908379120603. The next prime is 16908379120663. The reversal of 16908379120641 is 14602197380961.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 16908379120641 - 27 = 16908379120513 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (16908379124641) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2818063186771 + ... + 2818063186776.
It is an arithmetic number, because the mean of its divisors is an integer number (5636126373548).
Almost surely, 216908379120641 is an apocalyptic number.
It is an amenable number.
16908379120641 is a deficient number, since it is larger than the sum of its proper divisors (5636126373551).
16908379120641 is an equidigital number, since it uses as much as digits as its factorization.
16908379120641 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5636126373550.
The product of its (nonzero) digits is 3919104, while the sum is 57.
The spelling of 16908379120641 in words is "sixteen trillion, nine hundred eight billion, three hundred seventy-nine million, one hundred twenty thousand, six hundred forty-one".
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