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16917750993 = 311131923314171
BaseRepresentation
bin11111100000110000…
…00110010011010001
31121200000201210111010
433300120012103101
5234121421012433
611434422041133
71136144340123
oct176030062321
947600653433
1016917750993
1171a16a17a0
1233418791a9
131797c56460
14b66bcd213
1569037be63
hex3f06064d1

16917750993 has 256 divisors, whose sum is σ = 31213486080. Its totient is φ = 7983360000.

The previous prime is 16917750989. The next prime is 16917751001. The reversal of 16917750993 is 39905771961.

It is not a de Polignac number, because 16917750993 - 22 = 16917750989 is a prime.

It is a super-2 number, since 2×169177509932 (a number of 21 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (57).

It is not an unprimeable number, because it can be changed into a prime (16917750973) by changing a digit.

It is a polite number, since it can be written in 255 ways as a sum of consecutive naturals, for example, 238278148 + ... + 238278218.

It is an arithmetic number, because the mean of its divisors is an integer number (121927680).

Almost surely, 216917750993 is an apocalyptic number.

16917750993 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

16917750993 is a deficient number, since it is larger than the sum of its proper divisors (14295735087).

16917750993 is a wasteful number, since it uses less digits than its factorization.

16917750993 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 212.

The product of its (nonzero) digits is 3214890, while the sum is 57.

The spelling of 16917750993 in words is "sixteen billion, nine hundred seventeen million, seven hundred fifty thousand, nine hundred ninety-three".