16922648343 has 4 divisors (see below), whose sum is σ = 22563531128. Its totient is φ = 11281765560.

The previous prime is 16922648341. The next prime is 16922648359. The reversal of 16922648343 is 34384622961.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 16922648343 - 2¹ = 16922648341 is a prime.

It is a super-3 number, since 3×16922648343³ (a number of 32 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 16922648292 and 16922648301.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (16922648341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2820441388 + ... + 2820441393.

It is an arithmetic number, because the mean of its divisors is an integer number (5640882782).

Almost surely, 2^16922648343 is an apocalyptic number.

16922648343 is a deficient number, since it is larger than the sum of its proper divisors (5640882785).

16922648343 is an equidigital number, since it uses as much as digits as its factorization.

16922648343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5640882784.

The product of its digits is 1492992, while the sum is 48.

The spelling of 16922648343 in words is "sixteen billion, nine hundred twenty-two million, six hundred forty-eight thousand, three hundred forty-three".