Base | Representation |
---|---|
bin | 11111101000011101… |
… | …10000101100000011 |
3 | 1121211112101220202112 |
4 | 33310032300230003 |
5 | 234234444141120 |
6 | 11445052005535 |
7 | 1140561056231 |
oct | 176416605403 |
9 | 47745356675 |
10 | 16982412035 |
11 | 7225146576 |
12 | 335b4608ab |
13 | 17a8475b24 |
14 | b71621951 |
15 | 695da0bc5 |
hex | 3f43b0b03 |
16982412035 has 16 divisors (see below), whose sum is σ = 21096936000. Its totient is φ = 13107916416.
The previous prime is 16982411981. The next prime is 16982412047. The reversal of 16982412035 is 53021428961.
16982412035 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 16982412035 - 28 = 16982411779 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 16982411983 and 16982412001.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 160997 + ... + 244713.
It is an arithmetic number, because the mean of its divisors is an integer number (1318558500).
Almost surely, 216982412035 is an apocalyptic number.
16982412035 is a deficient number, since it is larger than the sum of its proper divisors (4114523965).
16982412035 is a wasteful number, since it uses less digits than its factorization.
16982412035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 85150.
The product of its (nonzero) digits is 103680, while the sum is 41.
The spelling of 16982412035 in words is "sixteen billion, nine hundred eighty-two million, four hundred twelve thousand, thirty-five".
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