Base | Representation |
---|---|
bin | 1001111001110000001… |
… | …1010111110010100001 |
3 | 121021010002021121112121 |
4 | 2132130003113302201 |
5 | 10241402143312423 |
6 | 210053005424241 |
7 | 15201530620651 |
oct | 2363403276241 |
9 | 537102247477 |
10 | 170121854113 |
11 | 6616a395a52 |
12 | 28b7956b081 |
13 | 1307227cc03 |
14 | 833bd16361 |
15 | 465a3ba45d |
hex | 279c0d7ca1 |
170121854113 has 16 divisors (see below), whose sum is σ = 185383918080. Its totient is φ = 155461752576.
The previous prime is 170121854101. The next prime is 170121854141. The reversal of 170121854113 is 311458121071.
170121854113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 170121854113 - 25 = 170121854081 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (170121854153) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 18970 + ... + 583612.
It is an arithmetic number, because the mean of its divisors is an integer number (11586494880).
Almost surely, 2170121854113 is an apocalyptic number.
It is an amenable number.
170121854113 is a deficient number, since it is larger than the sum of its proper divisors (15262063967).
170121854113 is a wasteful number, since it uses less digits than its factorization.
170121854113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 565176.
The product of its (nonzero) digits is 6720, while the sum is 34.
Adding to 170121854113 its reverse (311458121071), we get a palindrome (481579975184).
The spelling of 170121854113 in words is "one hundred seventy billion, one hundred twenty-one million, eight hundred fifty-four thousand, one hundred thirteen".
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