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17103126149 = 139912225251
BaseRepresentation
bin11111110110110110…
…01111111010000101
31122010221112211101122
433323123033322011
5240011400014044
611505043203325
71143555113354
oct177333177205
948127484348
1017103126149
1172872a58aa
123393976545
1317c748cab5
14b8368599b
156a1797dee
hex3fb6cfe85

17103126149 has 4 divisors (see below), whose sum is σ = 17115352800. Its totient is φ = 17090899500.

The previous prime is 17103126121. The next prime is 17103126181. The reversal of 17103126149 is 94162130171.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-17103126149 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (17103126109) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6111227 + ... + 6114024.

It is an arithmetic number, because the mean of its divisors is an integer number (4278838200).

Almost surely, 217103126149 is an apocalyptic number.

It is an amenable number.

17103126149 is a deficient number, since it is larger than the sum of its proper divisors (12226651).

17103126149 is a wasteful number, since it uses less digits than its factorization.

17103126149 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12226650.

The product of its (nonzero) digits is 9072, while the sum is 35.

The spelling of 17103126149 in words is "seventeen billion, one hundred three million, one hundred twenty-six thousand, one hundred forty-nine".

Divisors: 1 1399 12225251 17103126149