Base | Representation |
---|---|
bin | 1111100100000011110010… |
… | …1101011001100011000001 |
3 | 2020120220111102112021112201 |
4 | 3321000330231121203001 |
5 | 4220331210032210340 |
6 | 100221115505153201 |
7 | 3414212324052352 |
oct | 371007455314301 |
9 | 66526442467481 |
10 | 17112168241345 |
11 | 54a825894a271 |
12 | 1b0455262b801 |
13 | 971894242a98 |
14 | 43233a4b9d29 |
15 | 1ea1d7c8179a |
hex | f903cb598c1 |
17112168241345 has 32 divisors (see below), whose sum is σ = 21685503744000. Its totient is φ = 12927149634816.
The previous prime is 17112168241283. The next prime is 17112168241351. The reversal of 17112168241345 is 54314286121171.
It is a cyclic number.
It is not a de Polignac number, because 17112168241345 - 233 = 17103578306753 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 17112168241295 and 17112168241304.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 495284131 + ... + 495318679.
It is an arithmetic number, because the mean of its divisors is an integer number (677671992000).
Almost surely, 217112168241345 is an apocalyptic number.
It is an amenable number.
17112168241345 is a deficient number, since it is larger than the sum of its proper divisors (4573335502655).
17112168241345 is a wasteful number, since it uses less digits than its factorization.
17112168241345 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 51337.
The product of its digits is 322560, while the sum is 46.
The spelling of 17112168241345 in words is "seventeen trillion, one hundred twelve billion, one hundred sixty-eight million, two hundred forty-one thousand, three hundred forty-five".
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